Resultados Práctico 2 - 2023.1
2-1: a)
![\dfrac{\rho_1}{\rho_2}= 2 \dfrac{\rho_1}{\rho_2}= 2](https://eva.fing.edu.uy/filter/tex/pix.php/9cae1730ea1df7d03e2b17f331ff312b.png)
b) ![\dfrac{\dot{V_1}}{\dot{V_2}}=\dfrac{1}{2} \dfrac{\dot{V_1}}{\dot{V_2}}=\dfrac{1}{2}](https://eva.fing.edu.uy/filter/tex/pix.php/38cf090fb3c51002b67ae9e94c549197.png)
c)
![h_{2}=\dfrac{h}{4} \,\,\,, \,\,\, \dfrac{\dot{m_1}}{\dot{m_2}}=\dfrac{\rho_1}{\rho_2} h_{2}=\dfrac{h}{4} \,\,\,, \,\,\, \dfrac{\dot{m_1}}{\dot{m_2}}=\dfrac{\rho_1}{\rho_2}](https://eva.fing.edu.uy/filter/tex/pix.php/a7f3b41e6d5995cfcea87fcc1a690782.png)
2-2:
![v_{d} = 9,86 \,m/s v_{d} = 9,86 \,m/s](https://eva.fing.edu.uy/filter/tex/pix.php/2a6a2ba442f113cbcc7b17852802b2b8.png)
2-3:
![x = 0,35 \,m x = 0,35 \,m](https://eva.fing.edu.uy/filter/tex/pix.php/e2e0277ff8e8ea768129d3d932e9c9b9.png)
2-4: a)
b)
![v_{3} = 12,2 \,m/s v_{3} = 12,2 \,m/s](https://eva.fing.edu.uy/filter/tex/pix.php/c64c1c34ea2f27fab825c8bab4fb2b12.png)
c)
![t = 170 \,s t = 170 \,s](https://eva.fing.edu.uy/filter/tex/pix.php/2e9f565fb83c336220f0276a15d2ed6b.png)
2-5:
a) Para que no salte, ![h \leq \dfrac{m}{\rho L^2} -\dfrac{P_{0}}{\rho g} h \leq \dfrac{m}{\rho L^2} -\dfrac{P_{0}}{\rho g}](https://eva.fing.edu.uy/filter/tex/pix.php/b0e3d9cb895d47611e4735e3ab3483ef.png)
b) ![N=\frac{\rho}{2}v_{1}^{2}\left(\frac{S_{1}^{2}}{S_{2}^{2}}-1\right)L^2 N=\frac{\rho}{2}v_{1}^{2}\left(\frac{S_{1}^{2}}{S_{2}^{2}}-1\right)L^2](https://eva.fing.edu.uy/filter/tex/pix.php/4ec04d7120530f4cbb750da9e78a9cd7.png)
2-7: ![v = 0,84 \,m/s v = 0,84 \,m/s](https://eva.fing.edu.uy/filter/tex/pix.php/6ae0a664e60227b7aa8d6943701d98a8.png)
2-8: a) ![F_{fr} = 20,6 \,N F_{fr} = 20,6 \,N](https://eva.fing.edu.uy/filter/tex/pix.php/f044ac0cafb6b264e68c9a86a5e12413.png)
b) ![\Delta h = 0 \,m \Delta h = 0 \,m](https://eva.fing.edu.uy/filter/tex/pix.php/ff70109f0cb573ec6bb55519eb12f27e.png)
c) ![v_{2} = 20,3 \,m/s v_{2} = 20,3 \,m/s](https://eva.fing.edu.uy/filter/tex/pix.php/2b4e964fce3ba365eb31264d1cd2c215.png)
d) ![\Delta h = -1,25 \,m \Delta h = -1,25 \,m](https://eva.fing.edu.uy/filter/tex/pix.php/37349f86f8fecfc7813ebfad5a6bc4fe.png)
2-9: a) ![P_{1}-P_{2} = 16\,kPa P_{1}-P_{2} = 16\,kPa](https://eva.fing.edu.uy/filter/tex/pix.php/2e687532c795edc04aa1cc58d3124fda.png)
![P_{2}-P_{3} = -17,28\,kPa P_{2}-P_{3} = -17,28\,kPa](https://eva.fing.edu.uy/filter/tex/pix.php/97e2af3abdf10b5ef5feeac22fadb58d.png)
c) ![h_{1} = 17,69 \,cm h_{1} = 17,69 \,cm](https://eva.fing.edu.uy/filter/tex/pix.php/81c2714743cac9d104313469bd551e9f.png)
![h_{2} = 30,65 \,cm h_{2} = 30,65 \,cm](https://eva.fing.edu.uy/filter/tex/pix.php/3b26b3ab11d8938a502ec2fbd7182085.png)
![h_{3} = 16,66 \,cm h_{3} = 16,66 \,cm](https://eva.fing.edu.uy/filter/tex/pix.php/605d245c57f3564656bd583c031a27cf.png)
2-10: a) ![v=\sqrt{2g(d+h_{2})} v=\sqrt{2g(d+h_{2})}](https://eva.fing.edu.uy/filter/tex/pix.php/92e17653f2449ac11eddbfbc8b62a72e.png)
b) ![P_{B} = P_{0} -\rho g(h_{1}+d+h_{2}) P_{B} = P_{0} -\rho g(h_{1}+d+h_{2})](https://eva.fing.edu.uy/filter/tex/pix.php/3392edadf57578552b2ee5c125f33f6b.png)
c) ![h_{1}^{max}=\dfrac{P_{0}}{\rho g}-(h_{2}+d) h_{1}^{max}=\dfrac{P_{0}}{\rho g}-(h_{2}+d)](https://eva.fing.edu.uy/filter/tex/pix.php/67c0608c73b8cdb6f852946990ae5818.png)
Por lo tanto,
2-11: a) ![T = \dfrac{L^{3}g}{2}(\rho' - \rho) T = \dfrac{L^{3}g}{2}(\rho' - \rho)](https://eva.fing.edu.uy/filter/tex/pix.php/389a27d5c5566c2efb020b800c3559fc.png)
b) ![d_{mín} = \dfrac{L}{\rho}\left(\rho'-2\dfrac{T_{máx}}{L^{3}g}\right) d_{mín} = \dfrac{L}{\rho}\left(\rho'-2\dfrac{T_{máx}}{L^{3}g}\right)](https://eva.fing.edu.uy/filter/tex/pix.php/d760432953b84a1415abe19370f50663.png)
2-12: a) ![S_{1} = 1,44 \times10^{-3}\,m^{2} S_{1} = 1,44 \times10^{-3}\,m^{2}](https://eva.fing.edu.uy/filter/tex/pix.php/622a3fe27513906bc516c37eae2a7092.png)
b) ![v_{4} = 2,06\,m/s v_{4} = 2,06\,m/s](https://eva.fing.edu.uy/filter/tex/pix.php/945fedd13c9528dc8ecf56ac40273de7.png)
2-13: a) ![Q_{0} = \dfrac{23}{10}\sqrt{2gH}S_{1} Q_{0} = \dfrac{23}{10}\sqrt{2gH}S_{1}](https://eva.fing.edu.uy/filter/tex/pix.php/6923623380ad144b32219a6a01c47185.png)
b) ![H_{máx} = \left(\dfrac{10}{23}v_{0}\right)^2 \cdot \dfrac{1}{2g} H_{máx} = \left(\dfrac{10}{23}v_{0}\right)^2 \cdot \dfrac{1}{2g}](https://eva.fing.edu.uy/filter/tex/pix.php/6ddd9efb88ad2f59db06dc84c64c83e3.png)
c) ![P_{1} = P_{0} - 4,29 \rho gH P_{1} = P_{0} - 4,29 \rho gH](https://eva.fing.edu.uy/filter/tex/pix.php/96b52631c64a44deb87770976f2483e1.png)
2-14: a) ![P_{Energia potencial} = 98\,W P_{Energia potencial} = 98\,W](https://eva.fing.edu.uy/filter/tex/pix.php/06395f680f3626c002469ca255d8380b.png)
![P_{Energia cinética} = 81\,W P_{Energia cinética} = 81\,W](https://eva.fing.edu.uy/filter/tex/pix.php/d45f6a2273e85f989cf765328b6a9811.png)
![P_{TOTAL} = 179\,W P_{TOTAL} = 179\,W](https://eva.fing.edu.uy/filter/tex/pix.php/040d60f4c48c02aca0b4e54b106119c5.png)
b) Ver solución del Examen de julio de 2014, Problema 1.
Última modificación: miércoles, 29 de marzo de 2023, 17:43