Fuente TeX:

\displaystyle \int_1^\sqrt{x} \sin(u^2)du = \displaystyle \int_1^\sqrt{x} 2u\sin(u^2)\frac{1}{2u}du = -\left( \frac{\cos(u^2)}{2u} \right) \left.\right|_1^{\sqrt{x}} - \displaystyle \frac{1}{2} \int_1^\sqrt{x} \frac{\cos(u^2)}{u^2} du